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Sine and cosine of complementary angles

20 practice questions 2 video lessons Theory + worked examples

Sine and Cosine of Complementary Angles

California Geometry • Standard G-SRT.7 • Right Triangles & Trigonometry

Sine and Cosine of Complementary Angles is a topic in Right Triangles & Trigonometry in the California Common Core State Standards. It is aligned to Standard G-SRT.7, which requires students to explain and use the relationship between the sine and cosine of complementary angles.

Sine and cosine of complementary angles are equal: \(\sin\theta=\cos(90^\circ-\theta)\).

California Geometry › Right Triangles & Trigonometry › Sine and Cosine of Complementary Angles  —  Standard G-SRT.7

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Practice questions

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Watch 2 video(s)
  • Showing relationship between cosine and sine of complements | Trigonometry | Khan Academy Watch
  • Sine and Cosine of Complementary Angles for the SAT - What You Need to Know Watch
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Theory

The two acute angles of a right triangle are complementary — they add to \(90^\circ\). This creates the cofunction relationship:

\[\sin\theta=\cos(90^\circ-\theta),\qquad \cos\theta=\sin(90^\circ-\theta).\]

The reason is that the side opposite one acute angle is the side adjacent to the other, so the same ratio is a sine for one angle and a cosine for its complement.

“Co” means complement. Sine and cosine are cofunctions because they pair complementary angles.
Complementary acute angles The two acute angles of a right triangle add to 90 degrees, so the sine of one equals the cosine of the other. θ 90°−θ the two acute angles are complementary
The two acute angles \(\theta\) and \(90^\circ-\theta\) are complementary.
Cofunction relationship Cofunction relationship Cofunction relationship sin θ = cos(90° − θ) cos θ = sin(90° − θ)
The cofunction identities.

The cofunction identities:

\[\sin\theta=\cos(90^\circ-\theta),\qquad \cos\theta=\sin(90^\circ-\theta)\]
sine theta equals cosine of ninety minus theta, and vice versa
Equal sine and cosine \(\Rightarrow\) complementary angles. Set the angles to sum to \(90^\circ\).

How to use the relationship

  1. Rewrite a sine as a cosine of the complement (or vice versa).
  2. To solve \(\sin A=\cos B\), set \(A+B=90^\circ\).
  3. Check with a known pair like \(\sin 30^\circ=\cos 60^\circ\).
Example 1 — A cofunction fact
Show that \(\sin 30^\circ=\cos 60^\circ\).
Solution

Since \(30^\circ\) and \(60^\circ\) are complementary, sine of one equals cosine of the other.

\(\sin 30^\circ\)\(=\)\(\cos(90^\circ-30^\circ)=\cos 60^\circ\)
sine of 30 equals cosine of 60
Example 2 — Rewrite as a cofunction
Rewrite \(\cos 25^\circ\) as a sine.
Solution

Use \(\cos\theta=\sin(90^\circ-\theta)\).

\(\cos 25^\circ\)\(=\)\(\sin 65^\circ\)
cosine of 25 equals sine of 65
Example 3 — Solve for the angle
If \(\sin(2x)=\cos(50^\circ)\), find \(x\).
Solution

Sine equals cosine when the angles are complementary.

\(2x+50^\circ\)\(=\)\(90^\circ\)
\(2x\)\(=\)\(40^\circ\)
\(x\)\(=\)\(20^\circ\)
x equals 20 degrees
Example 4 — Why it works
Why does \(\sin\theta=\cos(90^\circ-\theta)\)?
Solution

The side opposite \(\theta\) is the side adjacent to the other acute angle \(90^\circ-\theta\); the same ratio is sine for one and cosine for the other.

the opposite side of one angle is the adjacent side of the other

Common pitfalls

Sine pairs with cosine of the complement, not the same angle.
The angles sum to \(90^\circ\), not \(180^\circ\).
This holds for the acute angles of a right triangle — complementary by definition.

Frequently asked questions

What is the cofunction relationship?

\(\sin\theta=\cos(90^\circ-\theta)\): the sine of an angle equals the cosine of its complement.

Why does sin 30 equal cos 60?

Because \(30^\circ\) and \(60^\circ\) are complementary, and sine and cosine are cofunctions.

How do you solve sin A = cos B?

Set the angles complementary: \(A+B=90^\circ\), then solve.

Why are sine and cosine called cofunctions?

Because they relate complementary angles — “co” stands for complement.