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Pythagorean theorem (proof from similarity)

20 practice questions 2 video lessons Theory + worked examples

The Pythagorean Theorem

California Geometry • Standard G-SRT.4 • Right Triangles & Trigonometry

The Pythagorean Theorem is the opening topic of Right Triangles & Trigonometry in the California Common Core State Standards. It is aligned to Standard G-SRT.4, which requires students to prove the Pythagorean theorem using triangle similarity.

The Pythagorean theorem states \(a^2+b^2=c^2\) for the legs and hypotenuse of a right triangle, and can be proved from similar triangles.

California Geometry › Right Triangles & Trigonometry › The Pythagorean Theorem  —  Standard G-SRT.4

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Practice questions

Every question with a fully worked solution.

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Watch 2 video(s)
  • Proof of Pythagorean Theorem with Similar Triangles Watch
  • Pythagoras Theorem: Proof #2: Using 3 similar triangles Watch
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Theory

In a right triangle, the Pythagorean Theorem relates the two legs \(a,b\) and the hypotenuse \(c\) (the side opposite the right angle):

\[a^2+b^2=c^2.\]

It can be proved from similarity: the altitude to the hypotenuse splits the triangle into two smaller triangles similar to the whole, and combining their proportions gives the theorem.

The converse is a test: if \(a^2+b^2=c^2\), the triangle is right-angled.
The Pythagorean theorem In a right triangle the squares of the legs sum to the square of the hypotenuse. a b c a² + b² = c²
\(a^2+b^2=c^2\) for the legs and hypotenuse.
Proof from similarity The altitude to the hypotenuse splits the right triangle into two similar triangles, proving the Pythagorean theorem. altitude gives similar triangles ⇒ proof
The altitude creates similar triangles that prove the theorem.

The theorem and its rearrangement:

\[a^2+b^2=c^2,\qquad \text{leg}=\sqrt{c^2-(\text{other leg})^2}\]
a squared plus b squared equals c squared; a leg is the square root of the hypotenuse squared minus the other leg squared
The hypotenuse is always the longest side, opposite the right angle.

How to use the Pythagorean theorem

  1. Identify the hypotenuse (opposite the right angle) and the legs.
  2. Substitute into \(a^2+b^2=c^2\).
  3. Solve for the unknown side and simplify the radical.
  4. Converse: to test a right angle, check if the equation holds.
Example 1 — Find the hypotenuse
A right triangle has legs \(6\) and \(8\). Find the hypotenuse.
Solution

Apply \(a^2+b^2=c^2\).

\(c^2\)\(=\)\(6^2+8^2\)
\(=\)\(36+64=100\)
\(c\)\(=\)\(\sqrt{100}=10\)
the hypotenuse is 10
Example 2 — Find a leg
A right triangle has hypotenuse \(13\) and one leg \(5\). Find the other leg.
Solution

Rearrange to solve for the missing leg.

\(b^2\)\(=\)\(13^2-5^2\)
\(=\)\(169-25=144\)
\(b\)\(=\)\(\sqrt{144}=12\)
the other leg is 12
Example 3 — Converse: is it a right triangle?
Do sides \(9,12,15\) form a right triangle?
Solution

Check whether the two shorter squares sum to the longest square.

\(9^2+12^2\)\(=\)\(81+144=225\)
\(15^2\)\(=\)\(225\)

Equal, so yes — it is a right triangle.

yes, 9, 12, 15 is a right triangle
Example 4 — A word problem
A \(12\)-ft ladder rests \(5\) ft from a wall. How high up does it reach?
Solution

The ladder is the hypotenuse; solve for the height.

\(h^2\)\(=\)\(12^2-5^2=144-25=119\)
\(h\)\(=\)\(\sqrt{119}\approx 10.9\ \text{ft}\)
the ladder reaches about 10.9 feet

Common pitfalls

The hypotenuse is \(c\), the longest side. Don't put a leg in its place.
To find a leg, subtract. \(b^2=c^2-a^2\), not \(c^2+a^2\).
Only right triangles. The theorem does not apply to other triangles.

Frequently asked questions

What is the Pythagorean theorem?

For a right triangle, \(a^2+b^2=c^2\), where \(c\) is the hypotenuse and \(a,b\) are the legs.

How do you find a leg with the Pythagorean theorem?

Subtract: a leg equals \(\sqrt{c^2-(\text{other leg})^2}\).

What is the converse of the Pythagorean theorem?

If the squares of the two shorter sides sum to the square of the longest side, the triangle is a right triangle.

How is it proved from similarity?

The altitude to the hypotenuse creates two triangles similar to the original; their proportions combine to give \(a^2+b^2=c^2\).