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Law of Sines

20 practice questions 2 video lessons Theory + worked examples

The Law of Sines

California Geometry • Standard G-SRT.11 • Right Triangles & Trigonometry

The Law of Sines is a topic in Right Triangles & Trigonometry in the California Common Core State Standards. It is aligned to Standard G-SRT.11, which requires students to prove the Law of Sines and use it to solve problems involving general triangles.

The Law of Sines states \(\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}\), solving triangles from AAS, ASA, or the ambiguous SSA case.

California Geometry › Right Triangles & Trigonometry › The Law of Sines  —  Standard G-SRT.11

Practice 20 questions
Practice questions

Every question with a fully worked solution.

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Watch 2 video(s)
  • Law of Sines, Basic Introduction, AAS & SSA - One Solution, Two Solutions vs No Solution, Trigonomet Watch
  • Law of Sines... How? When? (NancyPi) Watch
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Theory

The Law of Sines works in any triangle, not just right triangles:

\[\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}.\]

Each side is labeled with the lowercase letter of its opposite angle. Use it when you know an angle and its opposite side plus one more part (AAS, ASA, or the ambiguous SSA).

Pair each side with its opposite angle. The proportion only works with matched side-angle pairs.
Law of Sines In any triangle each side divided by the sine of its opposite angle gives the same value. c a b A B C each side over the sine of its opposite angle
Each side pairs with the sine of its opposite angle.
Law of Sines Law of Sines Law of Sines a / sin A = b / sin B = c / sin C use for AAS, ASA (and SSA)
The Law of Sines and when to use it.

The Law of Sines:

\[\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}\]
a over sine A equals b over sine B equals c over sine C
Side over sine to find a side; sine over side to find an angle.

How to use the Law of Sines

  1. Match each side with its opposite angle.
  2. Set up a proportion with one complete pair and the unknown.
  3. Solve for the missing side or angle.
  4. Find the third angle first in ASA if needed.
Example 1 — Find a side
In a triangle, \(A=40^\circ\), \(B=75^\circ\), and side \(a=10\). Find side \(b\).
Solution

Use \(\dfrac{a}{\sin A}=\dfrac{b}{\sin B}\).

\(b\)\(=\)\(\dfrac{a\sin B}{\sin A}=\dfrac{10\sin 75^\circ}{\sin 40^\circ}\)
\(\approx\)\(15.0\)
side b is about 15.0
Example 2 — ASA
With \(A=50^\circ\), \(C=60^\circ\), included side \(b=8\), find \(a\).
Solution

First \(B=180^\circ-50^\circ-60^\circ=70^\circ\), then the Law of Sines.

\(a\)\(=\)\(\dfrac{b\sin A}{\sin B}=\dfrac{8\sin 50^\circ}{\sin 70^\circ}\)
\(\approx\)\(6.5\)
side a is about 6.5
Example 3 — Find an angle
Given \(a=12\), \(b=9\), \(A=55^\circ\), find angle \(B\).
Solution

Use \(\dfrac{\sin B}{b}=\dfrac{\sin A}{a}\).

\(\sin B\)\(=\)\(\dfrac{9\sin 55^\circ}{12}\approx 0.614\)
\(B\)\(\approx\)\(37.9^\circ\)
angle B is about 37.9 degrees
Example 4 — When to use it
Which triangle cases does the Law of Sines solve?
Solution

When you know an angle and its opposite side, plus one more piece — cases AAS, ASA, and the ambiguous SSA.

AAS, ASA, and the ambiguous SSA cases

Common pitfalls

Pair sides with opposite angles. The proportion fails otherwise.
Check the ambiguous SSA case — a supplementary angle may also work.
Find the third angle first in ASA to get an angle opposite the given side.

Frequently asked questions

What is the Law of Sines?

In any triangle, \(\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}\); each side is proportional to the sine of its opposite angle.

When do you use the Law of Sines?

When you know an angle and its opposite side plus one more part: AAS, ASA, or SSA.

How do you find a side with the Law of Sines?

Use side-over-sine: \(b=\dfrac{a\sin B}{\sin A}\).

How do you find an angle with the Law of Sines?

Use sine-over-side: \(\sin B=\dfrac{b\sin A}{a}\), then take the inverse sine.