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Algebra 2 Rational functions

Operations on rational expressions

20 practice questions 0 video lessons Theory + worked examples

Operations on Rational Expressions

Texas Algebra II (TEKS) • Standard 2A.7(B) • Rational Functions

Operations on Rational Expressions is a topic in Rational Functions in the Texas Essential Knowledge and Skills (Algebra II, §111.40). It is aligned to Standard 2A.7(B), which requires students to add, subtract, multiply, and divide rational expressions.

Rational expressions multiply by cancelling, divide by the reciprocal, and add over a common denominator.

Texas Algebra II (TEKS) › Rational Functions › Operations on Rational Expressions  —  Standard 2A.7(B)

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Theory

Rational expressions follow the rules for fractions:

  • Multiply: factor, cancel, then multiply straight across.
  • Divide: multiply by the reciprocal of the second.
  • Add / subtract: rewrite over a common denominator.
Factor first so you can cancel and find the least common denominator.
Operating on fractions Operating on fractions Operating on fractions multiply: factor, cancel, multiply divide: multiply by the reciprocal add/subtract: common denominator
The three operations.
Common denominator Common denominator Common denominator 1/x + 1/(x+1) = (x+1 + x) / (x(x+1)) = (2x+1) / (x(x+1))
Adding over a common denominator.

Division and addition:

\[\dfrac{a}{b}\div\dfrac{c}{d}=\dfrac{a}{b}\cdot\dfrac{d}{c},\qquad \dfrac{a}{b}+\dfrac{c}{d}=\dfrac{ad+bc}{bd}\]
divide by multiplying by the reciprocal; add over a common denominator
Simplify the result and note any excluded values.

How to operate

  1. Factor every numerator and denominator.
  2. For \(\times\), cancel then multiply; for \(\div\), flip the second.
  3. For \(\pm\), build a common denominator.
  4. Simplify and state restrictions.
Example 1 β€” Multiply
Multiply \(\dfrac{2}{x}\cdot\dfrac{x}{3}\).
Solution

Cancel the \(x\), then multiply.

\(\dfrac{2}{x}\cdot\dfrac{x}{3}\)\(=\)\(\dfrac{2}{3}\)
the product is two thirds
Example 2 β€” Add with a common denominator
Add \(\dfrac{1}{x}+\dfrac{1}{x+1}\).
Solution

Use the common denominator \(x(x+1)\).

\(\dfrac{(x+1)+x}{x(x+1)}\)\(=\)\(\dfrac{2x+1}{x(x+1)}\)
the sum is 2 x plus 1 over x times x plus 1
Example 3 β€” Divide
Simplify \(\dfrac{3}{x+2}\div\dfrac{6}{x-1}\).
Solution

Multiply by the reciprocal.

\(\dfrac{3}{x+2}\cdot\dfrac{x-1}{6}\)\(=\)\(\dfrac{x-1}{2(x+2)}\)
the quotient is x minus 1 over 2 times x plus 2
Example 4 β€” Subtract
Simplify \(\dfrac{x}{x-1}-\dfrac{1}{x-1}\).
Solution

Same denominator β€” subtract the numerators.

\(\dfrac{x-1}{x-1}\)\(=\)\(1,\ x\neq1\)
the difference is 1, with x not equal to 1

Common pitfalls

Flip the second fraction when dividing, not the first.
Use a common denominator before adding or subtracting.
Factor first to cancel and simplify.

Frequently asked questions

How do you multiply rational expressions?

Factor, cancel common factors, then multiply across.

How do you divide them?

Multiply by the reciprocal of the second expression.

How do you add them?

Rewrite over a common denominator, then add the numerators.

Should you simplify the answer?

Yes β€” factor and cancel, and state excluded values.