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Algebra 2 Rational functions

Excluded values and domain restrictions

20 practice questions 0 video lessons Theory + worked examples

Excluded Values and Domain Restrictions

Texas Algebra II (TEKS) • Standard 2A.6(J) • Rational Functions

Excluded Values and Domain Restrictions is a topic in Rational Functions in the Texas Essential Knowledge and Skills (Algebra II, §111.40). It is aligned to Standard 2A.6(J), which requires students to determine the values of the domain for which a rational function is undefined.

Excluded values make a denominator zero; a cancelled factor leaves a hole, an uncancelled one a vertical asymptote.

Texas Algebra II (TEKS) › Rational Functions › Excluded Values and Domain Restrictions  —  Standard 2A.6(J)

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Theory

An excluded value makes a denominator zero, so the function is undefined there:

  • Set each denominator factor equal to zero.
  • A factor that cancels with the numerator leaves a hole.
  • A factor that does not cancel gives a vertical asymptote.
Find excluded values before simplifying β€” cancelling can hide them.
Excluded value creates a hole A factor that cancels leaves a hole in the graph at the excluded value. x y hole at x=2
A cancelled factor leaves a hole at \(x=2\).
Excluded values Excluded values Excluded values set each denominator factor = 0 those x-values are excluded a cancelled factor β†’ hole an uncancelled factor β†’ asymptote
Finding excluded values.

Excluded values:

\[q(x)=0\ \Rightarrow\ x\ \text{is excluded}\]
set the denominator equal to zero to find excluded values
The domain is all reals except the excluded values.

How to find excluded values

  1. Factor the denominator.
  2. Set each factor equal to zero.
  3. Those \(x\)-values are excluded.
  4. Decide hole (cancels) vs asymptote (does not).
Example 1 β€” One excluded value
Find the excluded value of \(\dfrac{x+1}{x-3}\).
Solution

Set the denominator to zero.

\(x-3\)\(=\)\(0\)
\(x\)\(=\)\(3\ \text{(excluded)}\)
the excluded value is x equals 3
Example 2 β€” Two excluded values
Find the excluded values of \(\dfrac{5}{x^2-4}\).
Solution

Factor and set each factor to zero.

\(x^2-4\)\(=\)\((x-2)(x+2)\)
\(x\)\(=\)\(2,\ -2\)
the excluded values are 2 and negative 2
Example 3 β€” Factor the denominator
Find the excluded values of \(\dfrac{x}{x^2+x-6}\).
Solution

Factor the denominator.

\(x^2+x-6\)\(=\)\((x+3)(x-2)\)
\(x\)\(=\)\(-3,\ 2\)
the excluded values are negative 3 and 2
Example 4 β€” Domain in interval notation
State the domain of \(\dfrac{x+1}{x-3}\).
Solution

Exclude \(x=3\).

\(\text{domain}\)\(=\)\((-\infty,3)\cup(3,\infty)\)
all reals except 3

Common pitfalls

Find excluded values before cancelling β€” the restriction remains.
A cancelled factor is a hole, not an asymptote.
Factor fully to catch every excluded value.

Frequently asked questions

What is an excluded value?

An \(x\)-value that makes a denominator zero, where the function is undefined.

How do you find excluded values?

Set each denominator factor equal to zero.

What is the difference between a hole and an asymptote?

A cancelled factor gives a hole; an uncancelled one gives a vertical asymptote.

Do excluded values stay after simplifying?

Yes β€” the domain restriction remains even after cancelling.