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Algebra 2 Exponential and logarithmic functions

Natural logarithm and the number e

20 practice questions 0 video lessons Theory + worked examples

The Natural Logarithm and e

California Algebra 2 • Standard F-LE.4 • Exponential & Logarithmic Functions

The Natural Logarithm and e is a topic in Exponential & Logarithmic Functions in the California Common Core State Standards. It is aligned to Standard F-LE.4, which requires students to express a logarithm as the solution to an exponential model, including the natural base e.

The natural base \(e\approx2.718\) is the base of continuous growth, and the natural log \(\ln\) is the logarithm base \(e\) and the inverse of \(e^x\).

California Algebra 2 › Exponential & Logarithmic Functions › The Natural Logarithm and e  —  Standard F-LE.4

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Theory

The natural base \(e\approx2.718\) is the base of continuous growth. Its logarithm is the natural log:

\[\ln x=\log_e x,\qquad \ln(e^x)=x,\ \ e^{\ln x}=x.\]

Continuous growth is modeled by \(A=Pe^{rt}\).

\(e^x\) and \(\ln x\) are inverses, so each undoes the other.
The natural exponential and log e to the x and the natural log are inverses, reflected across y = x. x y ln x
\(e^x\) and \(\ln x\) are inverse functions.
The number e The number e The number e e ≈ 2.71828 (natural base) ln x = logₑ x continuous growth: A = Peʳᵗ
The natural base and continuous growth.

Natural log and growth:

\[\ln(e^x)=x,\qquad A=Pe^{rt}\]
ln of e to the x is x; continuous growth is P times e to the r t
Use \(\ln\) to solve equations with base \(e\).

How to use e and ln

  1. Recognize base \(e\) — apply \(\ln\).
  2. Use \(\ln(e^x)=x\) to unwrap exponents.
  3. For continuous growth, use \(A=Pe^{rt}\).
  4. Evaluate \(\ln\) with a calculator.
Example 1 — Basic values
Evaluate \(\ln e\) and \(\ln 1\).
Solution

Use the definition of \(\ln\).

\(\ln e\)\(=\)\(1\)
\(\ln 1\)\(=\)\(0\)
ln e is 1 and ln 1 is 0
Example 2 — Solve with ln
Solve \(e^x=7\).
Solution

Take the natural log of both sides.

\(x\)\(=\)\(\ln 7\)
\(\approx\)\(1.946\)
x equals natural log of 7, about 1.95
Example 3 — Continuous growth
\(\$500\) grows continuously at \(4\%\) for \(10\) years. Find the value.
Solution

Use \(A=Pe^{rt}\).

\(A\)\(=\)\(500e^{0.04(10)}\)
\(=\)\(500e^{0.4}\approx\$745.91\)
about 745 dollars and 91 cents
Example 4 — Inverse relationship
Simplify \(\ln(e^5)\).
Solution

\(\ln\) and \(e^x\) undo each other.

\(\ln(e^5)\)\(=\)\(5\)
ln of e to the 5 is 5

Common pitfalls

\(\ln\) is base \(e\), not base 10.
\(\ln(e^x)=x\) exactly — they cancel.
Use \(rt\) as one exponent in \(e^{rt}\).

Frequently asked questions

What is the number e?

The natural base, \(e\approx2.718\), used for continuous growth.

What is the natural logarithm?

\(\ln x=\log_e x\), the logarithm base \(e\).

What is \(\ln(e^x)\)?

\(x\) — the functions are inverses.

What models continuous growth?

\(A=Pe^{rt}\).