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Equations of parallel and perpendicular lines

20 practice questions 2 video lessons Theory + worked examples

Equations of Parallel and Perpendicular Lines

Texas Geometry (TEKS) • Standard G.2(C) • Coordinate Geometry

Equations of Parallel and Perpendicular Lines is a topic in Coordinate Geometry in the Texas Essential Knowledge and Skills (Geometry, §111.41). It is aligned to Standard G.2(C), which requires students to determine an equation of a line parallel or perpendicular to a given line through a given point.

To write a parallel or perpendicular line, keep the slope (parallel) or use its opposite reciprocal (perpendicular) in point-slope form.

Texas Geometry (TEKS) › Coordinate Geometry › Equations of Parallel and Perpendicular Lines  —  Standard G.2(C)

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Practice questions

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  • Writing Equations of Lines Parallel and Perpendicular to a Given Line Through a Point Watch
  • Equations of Parallel and Perpendicular Lines Explained! [Algebra] Watch
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Theory

To write a line through a point \((x_1,y_1)\), use point-slope form \(y-y_1=m(x-x_1)\). The slope \(m\) comes from the relationship:

  • Parallel to a line of slope \(m\): use the same slope \(m\).
  • Perpendicular to a line of slope \(m\): use the opposite reciprocal \(-\dfrac1m\).
Get the slope first, then plug the point into point-slope form and simplify.
A line parallel to a given line through a point The parallel line keeps the same slope and passes through the given point. P(2,5) given line parallel
A line parallel to the given line, passing through \(P\).
Equation of a line Equation of a line Equation of a line point-slope: y - y₁ = m(x - x₁) parallel: use the same m perpendicular: use m' = -1/m
Point-slope form and the slope rules.

Point-slope form with the right slope:

\[y-y_1=m(x-x_1),\qquad m_\parallel=m,\qquad m_\perp=-\dfrac1m\]
use point-slope form; a parallel line keeps the slope, a perpendicular line uses the opposite reciprocal
Perpendicular to a horizontal line is vertical (\(x=\text{constant}\)), and vice versa.

How to write the line

  1. Find the given slope \(m\).
  2. Choose the new slope: same for parallel, opposite reciprocal for perpendicular.
  3. Substitute the point and slope into \(y-y_1=m(x-x_1)\).
  4. Simplify to slope-intercept form if required.
Example 1 — Parallel through a point
Write the line through \((2,5)\) parallel to \(y=\dfrac12 x+1\).
Solution

Parallel means the same slope \(m=\dfrac12\); use point-slope.

\(y-5\)\(=\)\(\dfrac12(x-2)\)
\(y\)\(=\)\(\dfrac12 x-1+5\)
\(y\)\(=\)\(\dfrac12 x+4\)
the line is y equals one half x plus 4
Example 2 — Perpendicular through a point
Write the line through \((4,1)\) perpendicular to \(y=2x-3\).
Solution

Perpendicular slope is the opposite reciprocal of \(2\), namely \(-\dfrac12\).

\(y-1\)\(=\)\(-\dfrac12(x-4)\)
\(y\)\(=\)\(-\dfrac12 x+2+1\)
\(y\)\(=\)\(-\dfrac12 x+3\)
the line is y equals negative one half x plus 3
Example 3 — Parallel, slope from two points
Write the line through \((0,0)\) parallel to the line through \((1,2)\) and \((3,8)\).
Solution

Slope of the given line is \(\dfrac{8-2}{3-1}=3\); use it.

\(y-0\)\(=\)\(3(x-0)\)
\(y\)\(=\)\(3x\)
the line is y equals 3x
Example 4 — Perpendicular to a horizontal line
Write the line through \((5,2)\) perpendicular to \(y=7\).
Solution

\(y=7\) is horizontal, so the perpendicular is vertical through \(x=5\).

\(x\)\(=\)\(5\)
the line is x equals 5

Common pitfalls

Parallel keeps the slope; perpendicular uses the opposite reciprocal — don't mix them up.
Use the given point, not a point on the original line.
Horizontal and vertical special cases: perpendicular to \(y=c\) is \(x=k\).

Frequently asked questions

How do you write a line parallel to a given line?

Keep the same slope and use point-slope form with the given point.

How do you write a line perpendicular to a given line?

Use the opposite-reciprocal slope and point-slope form with the given point.

What is point-slope form?

\(y-y_1=m(x-x_1)\), a line of slope \(m\) through \((x_1,y_1)\).

What line is perpendicular to a horizontal line?

A vertical line \(x=\text{constant}\), and a horizontal line is perpendicular to a vertical one.