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Pre-Calculus Trigonometric functions

Linear and angular velocity

20 practice questions 0 video lessons Theory + worked examples

Linear and Angular Velocity

Texas Precalculus (TEKS) • Standard P.4(D) • Trigonometric Functions

Linear and Angular Velocity is a topic in Trigonometric Functions in the Texas Essential Knowledge and Skills (Precalculus, §111.42). It is aligned to Standard P.4(D), which requires students to represent angles in applications of linear and angular velocity.

Angular velocity \(\omega=\dfrac{\theta}{t}\) measures how fast an angle turns, and linear velocity \(v=r\omega\) measures how fast a point on the rim travels.

Texas Precalculus (TEKS) › Trigonometric Functions › Linear and Angular Velocity  —  Standard P.4(D)

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Theory

When something rotates, two speeds describe it:

  • Angular velocity \(\omega\) — how fast the angle changes: \(\omega=\dfrac{\theta}{t}\), in radians per unit time.
  • Linear velocity \(v\) — how fast a point on the rim travels along its circular path: distance per unit time.

They are connected through the radius:

\[v=r\omega.\]
Convert revolutions to radians first. One revolution is \(2\pi\) radians, so rpm becomes rad/s by multiplying by \(2\pi\) and dividing by 60.
Angular and linear velocity on a rotating wheel A point on the rim of a wheel of radius r moves with linear velocity v equals r omega, where omega is the angular velocity. rv = rω
A rim point of a wheel of radius \(r\) moves at \(v=r\omega\).
Linear velocity equals radius times angular velocity Linear velocity v equals radius r times angular velocity omega; angular velocity is angle over time. v = rωω = θ / t (rad per unit time)v = distance / time (length per unit time)
Angular velocity \(\omega=\theta/t\); linear velocity \(v=r\omega\).

The rotation relationships:

\[\omega=\dfrac{\theta}{t},\qquad v=\dfrac{s}{t}=r\omega,\qquad s=r\theta\]
omega equals theta over t; v equals r omega; arc length s equals r theta
Units must match. \(\theta\) in radians, and the same time unit throughout, so \(v\) comes out in length per time.

How to solve rotation problems

  1. Convert revolutions to radians (\(\times 2\pi\)) and fix the time units.
  2. Find \(\omega\) in rad per unit time.
  3. Apply \(v=r\omega\) for the linear speed, or \(s=r\theta\) for distance.
  4. Rearrange if you need \(r\), \(\omega\), or \(t\) instead.
Example 1 — Angular velocity from rpm
A wheel spins at \(30\) revolutions per minute. Find its angular velocity in radians per second.
Solution

Each revolution is \(2\pi\) rad; convert minutes to seconds.

\(\omega\)\(=\)\(30\cdot\dfrac{2\pi\ \text{rad}}{60\ \text{s}}\)
\(=\)\(\pi\ \text{rad/s}\)
angular velocity is pi radians per second
Example 2 — Linear velocity
A point sits \(0.5\ \text{m}\) from the center of that wheel (\(\omega=\pi\) rad/s). Find its linear speed.
Solution

Use \(v=r\omega\).

\(v\)\(=\)\(0.5\cdot\pi\)
\(=\)\(\dfrac{\pi}{2}\ \text{m/s}\approx 1.57\ \text{m/s}\)
linear speed is pi over 2 meters per second
Example 3 — Find the radius
A tire rolls so a rim point moves at \(20\ \text{ft/s}\) while the wheel turns at \(8\) rad/s. Find the tire's radius.
Solution

Solve \(v=r\omega\) for \(r\).

\(r\)\(=\)\(\dfrac{v}{\omega}=\dfrac{20}{8}\)
\(=\)\(2.5\ \text{ft}\)
radius is 2.5 feet
Example 4 — Distance traveled
How far does a point \(3\ \text{ft}\) from the center travel when the wheel turns through \(\dfrac{4\pi}{3}\) rad?
Solution

Arc length \(s=r\theta\).

\(s\)\(=\)\(3\cdot\dfrac{4\pi}{3}\)
\(=\)\(4\pi\ \text{ft}\)
distance is 4 pi feet

Common pitfalls

Convert rpm to rad/s before using \(v=r\omega\). Revolutions and radians are not interchangeable.
Angular velocity uses radians, not degrees. \(v=r\omega\) requires \(\omega\) in rad per unit time.
Keep the radius consistent with the answer's units. A radius in feet gives a speed in feet per time.

Frequently asked questions

What is the difference between linear and angular velocity?

Angular velocity is how fast the angle turns (radians per time); linear velocity is how fast a rim point moves along its path (distance per time). They relate by \(v=r\omega\).

How do you convert rpm to radians per second?

Multiply revolutions by \(2\pi\) radians and divide by 60 seconds: \(\text{rpm}\times\dfrac{2\pi}{60}\).

What is the formula linking the two velocities?

\(v=r\omega\): linear velocity equals radius times angular velocity, with \(\omega\) in radians per unit time.

Why must angles be in radians here?

Because \(v=r\omega\) and \(s=r\theta\) come from the arc-length relationship, which only holds when the angle is in radians.