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Pre-Algebra Probability (introductory)

Probability of compound events

20 practice questions 0 video lessons Theory + worked examples

Probability of Compound Events

Texas Pre-Algebra (TEKS) • Standard 7.6(I) • Probability

Probability of Compound Events is a topic in Probability in the Texas Essential Knowledge and Skills. It is aligned to Standard 7.6(I), which requires students to find the probability of compound events.

A compound event combines two or more simple events; for independent events, multiply the probabilities.

Texas Pre-Algebra (TEKS) › Probability › Probability of Compound Events  —  Standard 7.6(I)

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Theory

A compound event involves two or more simple events.

Independent events: \(P(A\text{ and }B)=P(A)\cdot P(B)\); otherwise count the full sample space.
Two-dice sample space Compound events use the full sample space of outcomes. 1 1 2 2 3 3 4 4 5 5 6 6 sum = 7 (6 of 36)
The two-dice sample space.
Compound events Compound events Compound events independent: P(A and B) = P(A)Β·P(B) 'or' events: add, subtract overlap count outcomes in the sample space
Compound events.

Independent 'and':

\[P(A\text{ and }B)=P(A)\cdot P(B)\]
for independent events, multiply the probabilities
List or count the sample space when unsure.

How to find a compound probability

  1. Decide if the events are independent.
  2. Independent 'and': multiply.
  3. Otherwise, count favorable outcomes in the sample space.
  4. Divide by the total outcomes.
Example 1 β€” Two coins
Find \(P(\text{two heads})\) on two coins.
Solution

Multiply independent probabilities.

\(\dfrac{1}{2}\cdot\dfrac{1}{2}\)\(=\)\(\dfrac{1}{4}\)
one fourth
Example 2 β€” Two dice sum
Find \(P(\text{sum}=7)\) with two dice.
Solution

Six favorable of \(36\).

\(\dfrac{6}{36}\)\(=\)\(\dfrac{1}{6}\)
one sixth
Example 3 β€” And (independent)
\(P(\text{head})\) then \(P(\text{roll }6)\)?
Solution

Multiply.

\(\dfrac{1}{2}\cdot\dfrac{1}{6}\)\(=\)\(\dfrac{1}{12}\)
one twelfth
Example 4 β€” Count
How many outcomes for two dice?
Solution

\(6\times6\).

\(6\cdot6\)\(=\)\(36\)
36

Common pitfalls

Multiply only for independent 'and' events.
Count the full sample space when needed.
Two dice have \(36\) outcomes, not \(12\).

Frequently asked questions

What is a compound event?

An event combining two or more simple events.

How do I find P(A and B) for independent events?

Multiply \(P(A)\) and \(P(B)\).

How many outcomes for two dice?

\(36\).

\(P(\text{sum}=7)\)?

\(\dfrac16\).