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Algebra Single-variable equations

Literal equations and formulas

20 practice questions 2 video lessons Theory + worked examples
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Practice questions

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Theory

A literal equation (or formula) has more than one variable. To solve for one:

  1. Treat the other letters as constants.
  2. Use inverse operations on both sides.
  3. Isolate the target variable.
The steps are the same as any equation β€” only the “numbers” are letters.
Rearranging a formula Rearranging a formula Rearranging a formula treat other letters as constants isolate the target variable use inverse operations, both sides
Isolate the target variable.
Examples Examples Examples A = lw β†’ w = A / l d = rt β†’ t = d / r y = mx + b β†’ x = (y - b) / m
Rearranged formulas.

The idea:

\[A=lw\ \Rightarrow\ w=\dfrac{A}{l}\]
rearrange a formula to solve for a chosen variable
Whatever undoes the operation on the target variable, apply to both sides.

How to rearrange a formula

  1. Identify the variable to isolate.
  2. Treat the rest as constants.
  3. Undo operations with inverses, both sides.
  4. Write the target variable alone.
Example 1 β€” Solve for a factor
Solve \(A=lw\) for \(w\).
Solution

Divide both sides by \(l\).

\(w\)\(=\)\(\dfrac{A}{l}\)
w equals A over l
Example 2 β€” A rate formula
Solve \(d=rt\) for \(t\).
Solution

Divide by \(r\).

\(t\)\(=\)\(\dfrac{d}{r}\)
t equals d over r
Example 3 β€” Two steps
Solve \(P=2l+2w\) for \(l\).
Solution

Subtract, then divide.

\(P-2w\)\(=\)\(2l\)
\(l\)\(=\)\(\dfrac{P-2w}{2}\)
l equals P minus 2 w over 2
Example 4 β€” Solve a line for x
Solve \(y=mx+b\) for \(x\).
Solution

Undo the addition, then the multiplication.

\(y-b\)\(=\)\(mx\)
\(x\)\(=\)\(\dfrac{y-b}{m}\)
x equals y minus b over m

Common pitfalls

Apply operations to the whole side, not just one term.
Treat other letters as numbers while solving.
Divide the entire other side when isolating.

Frequently asked questions

What is a literal equation?

An equation with several variables, such as a formula.

How do you solve \(A=lw\) for \(w\)?

Divide both sides by \(l\): \(w=\dfrac{A}{l}\).

Is rearranging a formula different from solving an equation?

No β€” the same inverse-operation steps apply.

Why treat other variables as constants?

Because you are isolating just one of them.