Algebra
Sequences (as functions)
Geometric sequences
20 practice questions
2 video lessons
Theory + worked examples
Theory
A geometric sequence multiplies by a constant common ratio \(r\):
\[a_n=a_1\,r^{\,n-1}.\]
It behaves like an exponential function of \(n\).
Divide consecutive terms to find the ratio \(r\).
Terms multiply by \(r=2\) each step.
The geometric rule.
nth term:
\[a_n=a_1\,r^{\,n-1}\]
The exponent is \(n-1\).
How to work with geometric sequences
- Find the common ratio \(r\).
- Identify the first term \(a_1\).
- Use \(a_n=a_1 r^{n-1}\).
- Substitute the term number \(n\).
Example 1 — Common ratio
Find the common ratio of \(3,6,12,24,\dots\).
Solution
Divide consecutive terms.
| \(\dfrac{6}{3}\) | \(=\) | \(2\) |
Example 2 — nth term
Find the \(5\)th term of \(3,6,12,\dots\).
Solution
Use \(a_n=a_1 r^{n-1}\).
| \(a_5\) | \(=\) | \(3\cdot2^{4}=48\) |
Example 3 — Explicit rule
Write an explicit rule for \(3,6,12,\dots\).
Solution
Use \(a_1=3,r=2\).
| \(a_n\) | \(=\) | \(3\cdot2^{n-1}\) |
Example 4 — Recursive rule
Write a recursive rule for \(3,6,12,\dots\).
Solution
Each term doubles.
| \(a_1=3,\) | \(a_n=2a_{n-1}\) |
Common pitfalls
The exponent is \(n-1\), not \(n\).
A common ratio is multiplied, not added.
Divide consecutive terms to find \(r\).
Frequently asked questions
What is a geometric sequence?
A sequence with a constant ratio between terms.
What is the nth term formula?
\(a_n=a_1 r^{n-1}\).
How do you find the common ratio?
Divide any term by the one before it.
How is it like an exponential function?
The common ratio acts as the base.
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