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Algebra Sequences (as functions)

Geometric sequences

20 practice questions 2 video lessons Theory + worked examples
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Practice questions

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  • Explicit & recursive formulas for geometric sequences | High School Math | Khan Academy Watch
  • How to Write Formulas for Geometric Sequences (Recursive & Explicit) Watch
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Theory

A geometric sequence multiplies by a constant common ratio \(r\):

\[a_n=a_1\,r^{\,n-1}.\]

It behaves like an exponential function of \(n\).

Divide consecutive terms to find the ratio \(r\).
A geometric sequence Geometric terms multiply by a constant ratio, curving upward. n ×2 each step
Terms multiply by \(r=2\) each step.
Geometric sequence Geometric sequence Geometric sequence multiply by a common ratio r nth term: aₙ = a₁ · rⁿ⁻¹ like an exponential function
The geometric rule.

nth term:

\[a_n=a_1\,r^{\,n-1}\]
a sub n equals a one times r to the n minus 1
The exponent is \(n-1\).

How to work with geometric sequences

  1. Find the common ratio \(r\).
  2. Identify the first term \(a_1\).
  3. Use \(a_n=a_1 r^{n-1}\).
  4. Substitute the term number \(n\).
Example 1 — Common ratio
Find the common ratio of \(3,6,12,24,\dots\).
Solution

Divide consecutive terms.

\(\dfrac{6}{3}\)\(=\)\(2\)
the common ratio is 2
Example 2 — nth term
Find the \(5\)th term of \(3,6,12,\dots\).
Solution

Use \(a_n=a_1 r^{n-1}\).

\(a_5\)\(=\)\(3\cdot2^{4}=48\)
the fifth term is 48
Example 3 — Explicit rule
Write an explicit rule for \(3,6,12,\dots\).
Solution

Use \(a_1=3,r=2\).

\(a_n\)\(=\)\(3\cdot2^{n-1}\)
a sub n equals 3 times 2 to the n minus 1
Example 4 — Recursive rule
Write a recursive rule for \(3,6,12,\dots\).
Solution

Each term doubles.

\(a_1=3,\)\(a_n=2a_{n-1}\)
a one is 3 and each term doubles

Common pitfalls

The exponent is \(n-1\), not \(n\).
A common ratio is multiplied, not added.
Divide consecutive terms to find \(r\).

Frequently asked questions

What is a geometric sequence?

A sequence with a constant ratio between terms.

What is the nth term formula?

\(a_n=a_1 r^{n-1}\).

How do you find the common ratio?

Divide any term by the one before it.

How is it like an exponential function?

The common ratio acts as the base.