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Algebra Quadratic equations and functions

Factoring quadratic equations

20 practice questions 2 video lessons Theory + worked examples
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Practice questions

Every question with a fully worked solution.

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  • Factoring Quadratics WITHOUT Guessing Product & Sum Watch
  • Factoring Quadratics in 5 seconds! Trick for factorising easily Watch
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Theory

Factoring solves a quadratic using the zero product property: if a product is \(0\), one factor is \(0\).
  1. Write the quadratic in standard form (\(=0\)).
  2. Factor it.
  3. Set each factor equal to zero.
  4. Solve each for the roots.
Only works when the equation equals zero and factors nicely.
Factoring to find roots Factoring gives the roots directly: set each factor to zero. x y (x+2)(x+3)
Roots at \(x=-2\) and \(x=-3\).
Factoring to solve Factoring to solve Factoring to solve factor the quadratic zero product: set each factor = 0 xΒ² + 5x + 6 = (x+2)(x+3) roots: x = -2, x = -3
Factoring to solve.

Zero product property:

\[(x-p)(x-q)=0\ \Rightarrow\ x=p\ \text{or}\ x=q\]
if the product of factors is zero, each factor can be zero
Each factor set to zero gives a root.

How to factor and solve

  1. Set the equation to \(=0\).
  2. Factor the quadratic.
  3. Set each factor equal to zero.
  4. Solve for each root.
Example 1 β€” Factor and solve
Solve \(x^2+5x+6=0\).
Solution

Factor, then use the zero product property.

\((x+2)(x+3)\)\(=\)\(0\)
\(x\)\(=\)\(-2,\ -3\)
x equals negative 2 or negative 3
Example 2 β€” Difference of squares
Solve \(x^2-9=0\).
Solution

Factor the difference of squares.

\((x-3)(x+3)\)\(=\)\(0\)
\(x\)\(=\)\(3,\ -3\)
x equals 3 or negative 3
Example 3 β€” With a GCF
Solve \(2x^2+6x=0\).
Solution

Factor out \(2x\).

\(2x(x+3)\)\(=\)\(0\)
\(x\)\(=\)\(0,\ -3\)
x equals 0 or negative 3
Example 4 β€” Zero product property
Why does factoring solve a quadratic?
Solution

If a product is \(0\), at least one factor is \(0\) β€” the zero product property.

because a product is zero only if a factor is zero

Common pitfalls

Set the equation to zero first, then factor.
Set EACH factor to zero, not the product.
Don't divide by \(x\) β€” you'd lose the root \(x=0\).

Frequently asked questions

How does factoring solve a quadratic?

By the zero product property: set each factor to zero.

Solve \((x-4)(x+1)=0\).

\(x=4\) or \(x=-1\).

Do you set the equation to zero first?

Yes, before factoring.

Can you always factor a quadratic?

No β€” some need the quadratic formula.