Algebra
Absolute value equations and inequalities
Absolute value inequalities
19 practice questions
2 video lessons
Theory + worked examples
Theory
An absolute value inequality becomes a compound inequality:
- Less than: \(|X|<a\ \Rightarrow\ -a<X<a\) (between, “and”).
- Greater than: \(|X|>a\ \Rightarrow\ X<-a\) or \(X>a\) (outside, “or”).
Remember “less thAND, greatOR”: less-than is AND (between), greater-than is OR (outside).
\(|x|<4\): the values between.
\(|x|\ge3\): the values outside.
The two forms:
\[|X|<a\Rightarrow -a<X<a,\qquad |X|>a\Rightarrow X<-a\ \text{or}\ X>a\]
Isolate the absolute value first, then split.
How to solve
- Isolate the absolute value.
- Less-than \(\Rightarrow\) between; greater-than \(\Rightarrow\) outside.
- Write and solve the compound inequality.
- Graph on a number line.
Example 1 β Less than (between)
Solve \(|x|<4\).
Solution
“Less than” gives a between statement.
| \(-4\) | < | \(x<4\) |
Example 2 β Greater than (outside)
Solve \(|x|\ge3\).
Solution
“Greater than” gives an outside (or) statement.
| \(x\le-3\) | \(\text{or}\) | \(x\ge3\) |
Example 3 β Shifted
Solve \(|x-2|<5\).
Solution
Between statement, then solve.
| \(-5\) | < | \(x-2<5\) |
| \(-3\) | < | \(x<7\) |
Example 4 β Always true
Solve \(|x|>-1\).
Solution
Absolute value is always \(\ge0>-1\).
| \(|x|\) | \(>\) | \(-1\ \text{always}\) |
Common pitfalls
Less-than is between (and); greater-than is outside (or).
Isolate the absolute value first.
\(|X|>\)negative is always true (all reals).
Frequently asked questions
What does \(|x|<4\) mean?
\(-4<x<4\) β the values between.
What does \(|x|>3\) mean?
\(x<-3\) or \(x>3\) β the values outside.
Which is 'and' and which is 'or'?
Less-than is “and” (between); greater-than is “or” (outside).
When is an absolute value inequality always true?
When it says \(|X|>\) a negative number.
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