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Algebra 2 Exponential and logarithmic functions

Solving exponential equations (incl. with logs)

20 practice questions 0 video lessons Theory + worked examples

Solving Exponential Equations

Texas Algebra II (TEKS) • Standard 2A.5(D) • Exponential & Logarithmic Functions

Solving Exponential Equations is a topic in Exponential & Logarithmic Functions in the Texas Essential Knowledge and Skills (Algebra II, §111.40). It is aligned to Standard 2A.5(D), which requires students to solve exponential equations of the form y = ab to the x.

Exponential equations are solved by matching bases and equating exponents, or by taking a logarithm of both sides.

Texas Algebra II (TEKS) › Exponential & Logarithmic Functions › Solving Exponential Equations  —  Standard 2A.5(D)

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Theory

To solve an exponential equation, get the variable out of the exponent:

  • Same base: rewrite both sides with equal bases, then equate exponents.
  • Different bases: take a logarithm of both sides and use the power law.
Isolate the power first before taking a log.
Solving exponential equations Solving exponential equations Solving exponential equations same base? equate exponents different bases? take a log isolate the power first
Two strategies for exponential equations.
Take a log of both sides Take a log of both sides Take a log of both sides bˣ = k x·log b = log k x = log k / log b
Taking a log of both sides.

Log both sides:

\[b^x=k\ \Rightarrow\ x=\dfrac{\log k}{\log b}\]
b to the x equals k gives x equals log k over log b
Any base of log works — use \(\ln\) for base \(e\).

How to solve

  1. Isolate the exponential term.
  2. If bases can match, equate exponents.
  3. Otherwise take \(\log\) (or \(\ln\)) of both sides.
  4. Use the power law and solve for \(x\).
Example 1 — Same base
Solve \(2^x=16\).
Solution

Write \(16=2^4\) and equate exponents.

\(2^x\)\(=\)\(2^4\)
\(x\)\(=\)\(4\)
x equals 4
Example 2 — Take a log
Solve \(3^x=20\).
Solution

Take a log and use the power law.

\(x\log 3\)\(=\)\(\log 20\)
\(x\)\(=\)\(\dfrac{\log 20}{\log 3}\approx2.73\)
x is about 2.73
Example 3 — Rewrite the base
Solve \(5^{x+1}=125\).
Solution

\(125=5^3\).

\(x+1\)\(=\)\(3\)
\(x\)\(=\)\(2\)
x equals 2
Example 4 — Base e
Solve \(e^{2x}=10\).
Solution

Take the natural log.

\(2x\)\(=\)\(\ln 10\)
\(x\)\(=\)\(\dfrac{\ln 10}{2}\approx1.15\)
x is about 1.15

Common pitfalls

Isolate the power before taking a log.
The power law drops the exponent in front: \(\log b^x=x\log b\).
Keep it exact until the last step, then round.

Frequently asked questions

How do you solve \(2^x=8\)?

Write \(8=2^3\) and equate exponents: \(x=3\).

What if the bases don't match?

Take a logarithm of both sides and use the power law.

Which base of log should you use?

Any — base 10 or \(\ln\); use \(\ln\) for base \(e\).

Do you isolate the power first?

Yes — separate the exponential term before taking a log.