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Algebra 2 Sequences and series

Geometric sequences and series

20 practice questions 0 video lessons Theory + worked examples

Geometric Sequences and Series

Common Core Algebra 2 • Standard A-SSE.4 • Sequences & Series

Geometric Sequences and Series is a topic in Sequences & Series in the Common Core State Standards. It is aligned to Standard A-SSE.4, which requires students to derive and use the formula for the sum of a finite geometric series.

A geometric sequence multiplies by a constant ratio; its nth term is \(a_1 r^{n-1}\) and the sum is \(\dfrac{a_1(1-r^n)}{1-r}\).

Common Core Algebra 2 › Sequences & Series › Geometric Sequences and Series  —  Standard A-SSE.4

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Theory

A geometric sequence multiplies by a constant common ratio \(r\):

\[a_n=a_1\,r^{\,n-1},\qquad S_n=\dfrac{a_1(1-r^n)}{1-r}\ (r\neq1).\]
The terms grow (or shrink) exponentially — each is a fixed multiple of the last.
A geometric sequence Geometric terms multiply by a constant ratio, curving upward. n ×2 each step
Terms multiply by \(r=2\) each step.
Geometric formulas Geometric formulas Geometric formulas nth term: aₙ = a₁ · rⁿ⁻¹ sum: Sₙ = a₁(1 - rⁿ)/(1 - r) r = common ratio
The geometric formulas.

nth term and sum:

\[a_n=a_1\,r^{\,n-1},\qquad S_n=\dfrac{a_1(1-r^n)}{1-r}\]
the nth term multiplies by r to the n minus 1; the sum uses the geometric series formula
The exponent is \(n-1\) for the \(n\)th term.

How to work with geometric sequences

  1. Find \(a_1\) and the common ratio \(r\).
  2. Use \(a_n=a_1 r^{n-1}\) for a term.
  3. Use \(S_n=\dfrac{a_1(1-r^n)}{1-r}\) for a sum.
  4. Divide consecutive terms to find \(r\).
Example 1 — nth term
Find the \(5\)th term of \(2,6,18,54,\dots\).
Solution

Here \(a_1=2,\ r=3\).

\(a_5\)\(=\)\(2\cdot3^{4}\)
\(=\)\(2(81)=162\)
the fifth term is 162
Example 2 — Sum of terms
Find the sum of the first \(5\) terms of \(2,6,18,\dots\).
Solution

Use \(S_n=\dfrac{a_1(1-r^n)}{1-r}\).

\(S_5\)\(=\)\(\dfrac{2(1-3^5)}{1-3}\)
\(=\)\(\dfrac{2(-242)}{-2}=242\)
the sum is 242
Example 3 — Find the ratio
A geometric sequence has \(a_1=3\) and \(a_3=12\). Find \(r\) (positive).
Solution

Use \(a_3=a_1r^2\).

\(12\)\(=\)\(3r^2\)
\(r\)\(=\)\(2\)
the common ratio is 2
Example 4 — Growth pattern
A culture doubles every hour from \(100\). Find the count after \(4\) hours.
Solution

Geometric with \(r=2\); after 4 hours use the 5th term.

\(a\)\(=\)\(100\cdot2^{4}\)
\(=\)\(1600\)
there are 1600 after 4 hours

Common pitfalls

The exponent is \(n-1\), not \(n\).
A common ratio is multiplied, not added.
\(r\) can be negative — terms then alternate sign.

Frequently asked questions

What is a geometric sequence?

A sequence with a constant ratio between terms.

What is the nth term formula?

\(a_n=a_1 r^{n-1}\).

How do you find the common ratio?

Divide any term by the one before it.

How do you sum a geometric series?

\(S_n=\dfrac{a_1(1-r^n)}{1-r}\).