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Area of polygons (triangles, quadrilaterals)

20 practice questions 0 video lessons Theory + worked examples

Area of Polygons

California Geometry • Standard G-GPE.7 • Two-Dimensional Measurement

Area of Polygons is the opening topic of Two-Dimensional Measurement in the California Common Core State Standards. It is aligned to Standard G-GPE.7, which requires students to use coordinates and formulas to compute the areas of triangles and rectangles and other polygons.

Polygon area formulas include the triangle \(\dfrac12 bh\), the parallelogram \(bh\), and the trapezoid \(\dfrac12(b_1+b_2)h\).

California Geometry › Two-Dimensional Measurement › Area of Polygons  —  Standard G-GPE.7

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Theory

Each polygon has an area formula based on a base and a perpendicular height:

  • Triangle: \(A=\dfrac12 bh\).
  • Rectangle / parallelogram: \(A=bh\).
  • Trapezoid: \(A=\dfrac12(b_1+b_2)h\), where \(b_1,b_2\) are the parallel sides.
Height is always perpendicular to the base — not a slanted side.
Area of a triangle The area of a triangle is one half base times height. base b height h triangle: A = ½ b h
Triangle: \(A=\dfrac12 bh\), with height perpendicular to the base.
Area of a trapezoid A trapezoid's area is one half the sum of the parallel sides times the height. b₁ b₂ h trapezoid: A = ½(b₁+b₂)h
Trapezoid: \(A=\dfrac12(b_1+b_2)h\).

The area formulas:

\[\text{triangle } \dfrac12 bh,\quad \text{parallelogram } bh,\quad \text{trapezoid } \dfrac12(b_1+b_2)h\]
triangle area is one half base times height; parallelogram is base times height; trapezoid is one half the sum of parallel sides times height
The trapezoid uses the average of the two parallel sides times the height.

How to find a polygon's area

  1. Identify the shape and its base(s) and height.
  2. Use the perpendicular height, not a slant side.
  3. Substitute into the formula.
  4. Rearrange to find a missing dimension if the area is given.
Example 1 — Triangle area
Find the area of a triangle with base \(10\) and height \(6\).
Solution

Use \(A=\dfrac12 bh\).

\(A\)\(=\)\(\dfrac12(10)(6)=30\)
the area is 30 square units
Example 2 — Parallelogram area
Find the area of a parallelogram with base \(8\) and height \(5\).
Solution

A parallelogram's area is base times height.

\(A\)\(=\)\(8\times 5=40\)
the area is 40 square units
Example 3 — Trapezoid area
Find the area of a trapezoid with parallel sides \(6\) and \(10\) and height \(4\).
Solution

Use \(A=\dfrac12(b_1+b_2)h\).

\(A\)\(=\)\(\dfrac12(6+10)(4)\)
\(=\)\(\dfrac12(16)(4)=32\)
the area is 32 square units
Example 4 — Find a missing dimension
A triangle has area \(24\) and base \(8\). Find its height.
Solution

Solve \(\dfrac12 bh=24\).

\(\dfrac12(8)h\)\(=\)\(24\)
\(4h\)\(=\)\(24\)
\(h\)\(=\)\(6\)
the height is 6

Common pitfalls

Use the perpendicular height, not the slanted side length.
The trapezoid formula averages the two parallel sides; don't forget the \(\dfrac12\).
Area is in square units.

Frequently asked questions

What is the area of a triangle?

\(A=\dfrac12 bh\): one half the base times the perpendicular height.

What is the area of a trapezoid?

\(A=\dfrac12(b_1+b_2)h\): the average of the two parallel sides times the height.

What is the area of a parallelogram?

Base times perpendicular height, \(A=bh\).

What height do you use in area formulas?

Always the perpendicular height to the chosen base, not a slanted side.