Resources For Teachers For Tutors For Students & Parents Pricing
USA - Geometry Three-dimensional measurement

Composite 3D figures (surface area and volume)

20 practice questions 2 video lessons Theory + worked examples

Composite Three-Dimensional Figures

California Geometry • Standard G-GMD.3 • Three-Dimensional Measurement

Composite Three-Dimensional Figures is a topic in Three-Dimensional Measurement in the California Common Core State Standards. It is aligned to Standard G-GMD.3, which requires students to use volume and surface-area formulas for composite three-dimensional figures to solve problems.

A composite solid is split into familiar solids whose volumes and surface areas are added or subtracted.

California Geometry › Three-Dimensional Measurement › Composite Three-Dimensional Figures  —  Standard G-GMD.3

Practice 20 questions
Practice questions

Every question with a fully worked solution.

Start practising
Watch 2 video(s)
  • Math 10C: Surface Area and Volume of Composite Objects Watch
  • Composite Solids Lesson Watch
Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

A composite solid is built from several simple solids. Find its volume by decomposing:

  • Add the volumes of joined solids (a cylinder plus a hemisphere).
  • Subtract the volume of a hollow part or drilled hole.
Break it into pieces you know, compute each, then combine — the same idea as composite 2D areas, one dimension up.
Composite solid A composite solid is built from familiar solids whose volumes are added or subtracted. cylinder + hemisphere: add volumes
A cylinder with a hemisphere on top: add the volumes.
Composite solids Composite solids Composite solids split into familiar solids add joined volumes subtract hollow parts
The composite-solid strategy.

The strategy:

\[V_{\text{total}}=\sum V_{\text{parts}}\ \text{or}\ V_{\text{whole}}-V_{\text{hollow}}\]
add the volumes of the parts, or subtract a hollow part from the whole
Match radii and heights where solids join — a hemisphere on a cylinder shares the radius.

How to find a composite volume

  1. Break the solid into familiar solids.
  2. Compute each volume with its formula.
  3. Add joined parts; subtract hollow parts.
  4. Keep \(\pi\) exact when round solids appear.
Example 1 — Cylinder plus hemisphere
A solid is a cylinder (radius \(3\), height \(8\)) with a hemisphere (radius \(3\)) on top. Find the volume (leave \(\pi\)).
Solution

Add the cylinder and hemisphere volumes.

\(\text{cylinder}\)\(=\)\(\pi(3)^2(8)=72\pi\)
\(\text{hemisphere}\)\(=\)\(\dfrac12\cdot\dfrac43\pi(3)^3=18\pi\)
\(\text{total}\)\(=\)\(72\pi+18\pi=90\pi\)
the total volume is 90 pi
Example 2 — Subtract a hole
A cube of side \(6\) has a cylindrical hole of radius \(1\) and depth \(6\) through it. Find the remaining volume (leave \(\pi\)).
Solution

Subtract the cylinder from the cube.

\(\text{cube}\)\(=\)\(6^3=216\)
\(\text{cylinder}\)\(=\)\(\pi(1)^2(6)=6\pi\)
\(\text{remaining}\)\(=\)\(216-6\pi\)
the remaining volume is 216 minus 6 pi
Example 3 — Cone on a cylinder
A cylinder (radius \(2\), height \(5\)) is topped by a cone (radius \(2\), height \(3\)). Find the volume (leave \(\pi\)).
Solution

Add the two volumes.

\(\text{cylinder}\)\(=\)\(\pi(4)(5)=20\pi\)
\(\text{cone}\)\(=\)\(\dfrac13\pi(4)(3)=4\pi\)
\(\text{total}\)\(=\)\(24\pi\)
the total volume is 24 pi
Example 4 — The strategy
How do you find the volume of a composite solid?
Solution

Break it into familiar solids, find each volume, and add joined parts or subtract hollow parts.

decompose into solids, then add or subtract volumes

Common pitfalls

A hemisphere is half a sphere: \(\dfrac12\cdot\dfrac43\pi r^3\).
Add joined solids; subtract hollow ones. Decide which for each part.
Share the correct radius/height where the solids meet.

Frequently asked questions

How do you find the volume of a composite solid?

Split it into familiar solids, find each volume, and add joined parts or subtract hollow ones.

What is the volume of a hemisphere?

Half a sphere: \(\dfrac12\cdot\dfrac43\pi r^3=\dfrac23\pi r^3\).

When do you subtract volumes?

When part of the solid is hollow or drilled out — subtract that volume from the whole.

How is this like composite 2D area?

The same decompose-and-combine idea, but with volumes of solids instead of areas of shapes.