Design problems with geometric constraints
Geometric Design Problems
Geometric Design Problems is a topic in Modelling with Geometry in the California Common Core State Standards. It is aligned to Standard G-MG.3, which requires students to apply geometric methods to solve design problems, such as optimizing under constraints.
A design problem optimizes a shape — maximizing area, minimizing material, or lowering cost — subject to a geometric constraint.
Theory
A design problem asks for the best shape or size under a constraint:
- Objective: what to maximize or minimize (area, material, cost).
- Constraint: a fixed quantity (perimeter, area, budget).
- Feasibility: the answer must make physical sense.
A typical setup:
How to solve a design problem
- State the objective (what to maximize or minimize).
- Write the constraint as an equation.
- Substitute to get one variable, then optimize.
- Check units and that the answer is physically reasonable.
With perimeter \(2x+2y=40\), we have \(y=20-x\), so area \(A=x(20-x)\).
| \(A\) | \(=\) | \(20x-x^2\) |
| \(\text{vertex at } x\) | \(=\) | \(-\dfrac{20}{2(-1)}=10\) |
| \(y\) | \(=\) | \(20-10=10\) |
A \(10\times10\) square, area \(100\ \text{ft}^2\).
For a fixed area the perimeter is smallest when the rectangle is a square, so \(x=y=\sqrt{36}\).
| \(x=y\) | \(=\) | \(6\ \text{ft}\) |
| \(P\) | \(=\) | \(4(6)=24\ \text{ft}\) |
The circle's diameter equals the side, so \(r=4\).
| \(A\) | \(=\) | \(\pi(4)^2=16\pi\ \text{in}^2\) |
Multiply the area by the unit cost.
| \(\text{area}\) | \(=\) | \(12\times15=180\ \text{ft}^2\) |
| \(\text{cost}\) | \(=\) | \(180\times 3=\$540\) |
Common pitfalls
Frequently asked questions
What is a geometric design problem?
A problem that optimizes a shape (area, material, or cost) subject to a constraint like a fixed perimeter or budget.
What rectangle has the greatest area for a fixed perimeter?
A square — equal sides give the maximum area.
How do you set up a design problem?
Write the objective to optimize and the constraint equation, then use the constraint to reduce to one variable.
How do you find the cost of a design?
Multiply the area (or volume) by the cost per unit.