Resources For Teachers For Tutors For Students & Parents Pricing
USA - Geometry Circles

Chords and arcs (theorems and relationships)

20 practice questions 2 video lessons Theory + worked examples

Chords and Arcs

California Geometry • Standard G-C.2 • Circles

Chords and Arcs is a topic in Circles in the California Common Core State Standards. It is aligned to Standard G-C.2, which requires students to identify and describe relationships among inscribed angles, radii, and chords.

Chords and arcs are linked: congruent chords cut congruent arcs, and a diameter perpendicular to a chord bisects it.

California Geometry › Circles › Chords and Arcs  —  Standard G-C.2

Practice 20 questions
Practice questions

Every question with a fully worked solution.

Start practising
Watch 2 video(s)
  • Circles - Chords, Radius & Diameter - Basic Introduction - Geometry Watch
  • Geometry - Arcs and Chords Watch
Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

A chord is a segment joining two points on a circle. Several theorems connect chords, arcs, and the center:

  • A radius perpendicular to a chord bisects the chord (and its arc).
  • Congruent chords intercept congruent arcs.
  • Chords equidistant from the center are congruent.
The perpendicular-from-center trick creates a right triangle (radius, distance, half-chord) — use the Pythagorean theorem.
Perpendicular from center bisects a chord A radius perpendicular to a chord bisects the chord and its arc. radius ⊥ chord bisects the chord
A radius perpendicular to a chord bisects it.
Congruent chords Congruent chords in a circle intercept congruent arcs and are equidistant from the center. congruent chords cut congruent arcs
Congruent chords cut congruent arcs.

The right triangle from a chord:

\[r^2=d^2+\left(\dfrac{\text{chord}}{2}\right)^2\]
the radius squared equals the distance squared plus half the chord squared
Radius, center-distance, half-chord form a right triangle — solve with Pythagoras.

How to use chord theorems

  1. Drop a perpendicular from the center to the chord; it bisects the chord.
  2. Form the right triangle with radius, distance, and half-chord.
  3. Apply the Pythagorean theorem to find the missing length.
Example 1 — Perpendicular bisects the chord
A radius perpendicular to a chord meets it at \(M\). If the chord is \(16\), find the distance from \(M\) to one endpoint.
Solution

The perpendicular from the center bisects the chord.

\(\dfrac{16}{2}\)\(=\)\(8\)
half the chord is 8
Example 2 — Find the chord length
A chord is \(6\) from the center of a radius-\(10\) circle. Find the chord length.
Solution

The radius, the distance, and half the chord form a right triangle.

\(\text{half chord}\)\(=\)\(\sqrt{10^2-6^2}=\sqrt{64}=8\)
\(\text{chord}\)\(=\)\(2\times 8=16\)
the chord is 16
Example 3 — Congruent chords, congruent arcs
Two chords are congruent. What is true of their arcs?
Solution

Congruent chords intercept congruent arcs.

their arcs are congruent
Example 4 — Equidistant chords
Two chords are the same distance from the center. Are they congruent?
Solution

Yes — chords equidistant from the center are congruent.

yes, equidistant chords are congruent

Common pitfalls

The perpendicular from the center bisects the chord — use half the chord in the right triangle.
Congruent chords \(\Leftrightarrow\) congruent arcs \(\Leftrightarrow\) equal distance from center.
The radius is the hypotenuse of the chord right triangle, not a leg.

Frequently asked questions

What does a radius perpendicular to a chord do?

It bisects the chord and the arc the chord cuts off.

How do you find a chord's length from its distance to the center?

Use \(r^2=d^2+(\text{half chord})^2\), then double the half-chord.

What is true of congruent chords?

They intercept congruent arcs and are the same distance from the center.

Are chords equidistant from the center congruent?

Yes. Equal distance from the center means the chords are congruent.