Solving advanced exponential equations
Solving Exponential Equations
Solving Exponential Equations is a topic in Exponential & Logarithmic Functions in the California Common Core State Standards. It is aligned to Standard F-LE.4, which requires students to solve exponential equations, expressing the solution using logarithms.
Solving an exponential equation means matching bases to equate exponents, or taking a logarithm of both sides to bring the variable down.
Theory
An exponential equation has the unknown in an exponent. Two strategies cover almost every case:
- Same base: rewrite both sides with a common base, then set the exponents equal.
- Different bases: take a logarithm of both sides and use the power rule \(\log b^x=x\log b\) to bring the variable down.
The core moves:
How to solve an exponential equation
- Isolate the exponential expression.
- Same base? Rewrite and equate exponents.
- Otherwise take \(\ln\) of both sides.
- Bring the exponent down with the power rule and solve.
Write both sides with base 2, then equate exponents.
| \(2^x\) | \(=\) | \(2^5\) |
| \(x\) | \(=\) | \(5\) |
The bases can't be matched, so take \(\ln\) of both sides and use the power rule.
| \(\ln 3^x\) | \(=\) | \(\ln 20\) |
| \(x\ln 3\) | \(=\) | \(\ln 20\) |
| \(x\) | \(=\) | \(\dfrac{\ln 20}{\ln 3}\approx 2.73\) |
Take the natural log, which undoes \(e\).
| \(2x\) | \(=\) | \(\ln 7\) |
| \(x\) | \(=\) | \(\dfrac{\ln 7}{2}\approx 0.973\) |
Divide by 5 to isolate the power, then match bases.
| \(2^x\) | \(=\) | \(16\) |
| \(2^x\) | \(=\) | \(2^4\) |
| \(x\) | \(=\) | \(4\) |
Common pitfalls
Frequently asked questions
How do you solve an exponential equation?
Isolate the exponential, then either match bases and equate exponents, or take a logarithm of both sides and use the power rule.
When can you just equate exponents?
When both sides can be written with the same base. Then equal bases force equal exponents.
Which logarithm should you use?
Any base works; the natural log \(\ln\) is convenient because it is on every calculator.
Why take the log of both sides?
The power rule \(\ln b^x=x\ln b\) moves the variable out of the exponent so you can solve for it.