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Pre-Algebra Geometry

Area of triangles, quadrilaterals and polygons

20 practice questions 0 video lessons Theory + worked examples

Area of Triangles, Quadrilaterals and Polygons

California Pre-Algebra • Standard 6.G.1 • Geometry

Area of Triangles, Quadrilaterals and Polygons is the opening topic of Geometry in the California Common Core State Standards. It is aligned to Standard 6.G.1, which requires students to find the area of triangles, quadrilaterals, and polygons.

Area measures the space inside a shape; each polygon has a formula built from base and height.

California Pre-Algebra › Geometry › Area of Triangles, Quadrilaterals and Polygons  —  Standard 6.G.1

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Theory

Area is the number of unit squares that fit inside a shape.
  • Triangle: \(\dfrac{1}{2}bh\).
  • Rectangle: \(lw\); parallelogram: \(bh\).
  • Trapezoid: \(\dfrac{1}{2}(b_1+b_2)h\).
Height is perpendicular to the base.
Triangle area Triangle area is half the base times the height. base b height h
Base and height of a triangle.
Area formulas Area formulas Area formulas triangle: Β½ b h rectangle: l w parallelogram: b h trapezoid: Β½ (b₁+bβ‚‚) h
Area formulas.

Key areas:

\[A_{\triangle}=\dfrac{1}{2}bh,\quad A_{\square}=lw,\quad A_{\text{trap}}=\dfrac{1}{2}(b_1+b_2)h\]
triangle area is half base times height; rectangle is length times width
Area is in square units.

How to find area

  1. Identify the shape.
  2. Find the base and perpendicular height.
  3. Apply the matching formula.
  4. Label the answer in square units.
Example 1 β€” Triangle
Find the area of a triangle with base \(10\) and height \(6\).
Solution

Half base times height.

\(\dfrac{1}{2}(10)(6)\)\(=\)\(30\)
30 square units
Example 2 β€” Rectangle
Find the area of a \(8\times5\) rectangle.
Solution

Length times width.

\(8\cdot5\)\(=\)\(40\)
40 square units
Example 3 β€” Parallelogram
Find the area with base \(7\) and height \(4\).
Solution

Base times height.

\(7\cdot4\)\(=\)\(28\)
28 square units
Example 4 β€” Trapezoid
Bases \(6\) and \(10\), height \(4\). Find the area.
Solution

Average the bases, times height.

\(\dfrac{1}{2}(6+10)(4)\)\(=\)\(32\)
32 square units

Common pitfalls

Use the perpendicular height, not a slanted side.
Don't forget the \(\dfrac12\) for triangles.
Area is squared units.

Frequently asked questions

What is area?

The space inside a shape, in square units.

What is a triangle's area?

\(\dfrac12\) base times height.

What height do I use?

The perpendicular height.

Area of a \(10\times6\) triangle?

\(30\).