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Calculus Limits and continuity

Definition of a limit

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Definition of a Limit

California Calculus • Standard 1.0 • Limits and Continuity

Definition of a Limit is the opening topic of Limits and Continuity in the California Calculus Standards. It is aligned to Standard 1.0, which requires students to demonstrate knowledge of both the formal definition and the graphical interpretation of the limit of a function, including one-sided limits.

A limit is the value a function \(f(x)\) approaches as \(x\) approaches a fixed number \(a\), written \(\lim_{x\to a} f(x)=L\). Mastering this definition — left-hand and right-hand limits, when a two-sided limit exists, and when a limit does not exist — is the foundation for continuity, the derivative, and the integral later in the course.

California Calculus › Limits and Continuity › Definition of a Limit  —  Standard 1.0

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Theory

A limit describes the value a function approaches as its input gets close to a fixed number, written \(\lim_{x\to a} f(x)=L\). This page explains one-sided limits, when a two-sided limit exists, how to read a limit from a graph, how to evaluate one by direct substitution, and when a limit does not exist.

A limit is the single value a function heads toward as \(x\) gets close to a fixed number \(a\). We write

\[\lim_{x\to a} f(x)=L\]

which reads “the limit of \(f(x)\), as \(x\) approaches \(a\), equals \(L\).” It means \(f(x)\) gets as close as we like to \(L\) when \(x\) is close to \(a\) — on both sides of \(a\).

A one-sided limit looks at only one direction. The left-hand limit \(\lim_{x\to a^{-}} f(x)\) uses values with \(xright-hand limit \(\lim_{x\to a^{+}} f(x)\) uses values with \(x>a\).

Key idea: the two-sided limit exists only when the two one-sided limits agree. The limit depends on the values of \(f\) near \(a\), not on \(f(a)\) itself — the function need not even be defined at \(a\).
A function approaching the value L as x approaches a A smooth curve passes through the point where x equals a and y equals L, with dashed guide lines to the axes. x y a L f(x) → L
As \(x\to a\), \(f(x)\) approaches \(L\).
A jump where the one-sided limits differ, so the limit does not exist The left branch rises to an open circle at height L one; the right branch begins at a higher filled point L two, so the two-sided limit does not exist. x y a L₁ L₂ left ≠ right
A jump: \(\lim_{x\to a^{-}}\neq\lim_{x\to a^{+}}\), so the limit does not exist.

The limit notation and the test for existence:

\[\lim_{x\to a} f(x)=L\]

limit of f(x) as x approaches a equals L

The one-sided limits (from the left and from the right):

\[\lim_{x\to a^{-}} f(x)\qquad\text{and}\qquad\lim_{x\to a^{+}} f(x)\]

The two-sided limit exists exactly when they agree:

\[\lim_{x\to a} f(x)=L \iff \lim_{x\to a^{-}} f(x)=\lim_{x\to a^{+}} f(x)=L\]

two-sided limit exists when left limit equals right limit

Direct substitution: for the polynomial, root, and rational functions in this course, if substituting \(x=a\) gives a defined value then \(\lim_{x\to a} f(x)=f(a)\). Substitution is always the first thing to try.

How to find a limit

  1. Substitute \(x=a\) into \(f(x)\). If you get a single number, that is the limit.
  2. Simplify if substitution gives the indeterminate form \(\dfrac{0}{0}\): factor the top and bottom, cancel the common factor, then substitute again.
  3. Check both sides when the graph has a break at \(a\): find \(\lim_{x\to a^{-}}\) and \(\lim_{x\to a^{+}}\). If they are equal, that common value is the limit; if they differ, the limit does not exist.
Remember: the answer never depends on \(f(a)\). Ignore the value (or hole) exactly at \(a\) and look at what \(f(x)\) is heading toward.
Example 1 — Direct substitution
Evaluate \(\displaystyle\lim_{x\to 2}(3x+1)\).
Solution

The function is a polynomial, so substitute \(x=2\).

\(\lim_{x\to 2}(3x+1)\)\(=\)\(3\cdot 2+1\)
\(=\)\(6+1\)
\(=\)\(7\)

limit of 3x+1 as x approaches 2 = 7

Example 2 — Cancel a common factor
Evaluate \(\displaystyle\lim_{x\to 4}\dfrac{x^2-16}{x-4}\).
Solution

Substituting gives \(\dfrac{0}{0}\), so factor and cancel first.

\(\dfrac{x^2-16}{x-4}\)\(=\)\(\dfrac{(x-4)(x+4)}{x-4}\)
\(=\)\(x+4\)

Now substitute \(x=4\):

\(\lim_{x\to 4}(x+4)\)\(=\)\(4+4=8\)

limit equals 8

Example 3 — One-sided limits at a jump
The graph of \(g\) jumps at \(x=1\): it approaches \(2\) from the left and \(3\) from the right. Find \(\lim_{x\to 1} g(x)\).
A jump at x equals 1 with left limit 2 and right limit 3 The left branch rises to an open circle at height 2; the right branch starts at a filled point at height 3. x y 1 2 3
Solution

\(\lim_{x\to 1^{-}} g(x)\)\(=\)\(2\)
\(\lim_{x\to 1^{+}} g(x)\)\(=\)\(3\)

The one-sided limits differ (\(2\neq 3\)), so \(\lim_{x\to 1} g(x)\) does not exist.

Example 4 — The limit is not \(f(a)\)
A graph has a hole at \((1,4)\), but the point \(f(1)=1\) is plotted below it. Find \(\lim_{x\to 1} f(x)\).
A curve with a hole at height 4 and the actual point at height 1 A smooth curve approaches an open circle at height 4; a separate filled point sits lower at height 1, so the limit is 4 even though f of 1 equals 1. x y 1 4 1
Solution

The limit follows the curve, which heads to \(4\) from both sides. The plotted value \(f(1)=1\) does not matter.

\(\lim_{x\to 1} f(x)\)\(=\)\(4\)
\(f(1)\)\(=\)\(1\)

The limit is \(4\), even though \(f(1)=1\).

Common pitfalls

The limit is not \(f(a)\). Watch out for a hole in the graph: the function can be undefined at \(a\), or defined at a different height, while the limit is still the value the curve approaches.
\(\dfrac{0}{0}\) is not an answer. It is a signal to simplify — factor and cancel, then substitute again.
A jump means the limit does not exist. Even when both one-sided limits exist, if they are different numbers the two-sided limit does not exist.

Frequently asked questions

What is a limit in calculus?

The single value a function heads toward as \(x\) gets close to a fixed number \(a\). Formally, \(\lim_{x\to a} f(x)=L\) means \(f(x)\) gets arbitrarily close to \(L\) as \(x\) approaches \(a\) from both sides.

How do you find a limit?

Try direct substitution first. If you get a number, that is the limit. If you get \(\dfrac{0}{0}\), factor and cancel, then substitute. If the left and right sides disagree, the limit does not exist.

Does the function have to be defined at the point?

No. The limit depends only on values near \(a\), not on \(f(a)\). A function can have a hole at \(x=a\) and still have a limit there.

What does it mean when a limit does not exist?

Most often the left-hand and right-hand limits are different numbers — a jump in the graph. If the two sides do not agree on one value, the two-sided limit does not exist.

What is the difference between a one-sided and a two-sided limit?

A one-sided limit approaches \(a\) from only the left or only the right. The two-sided limit exists only when both one-sided limits are equal.