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Calculus Applications of integration

Area between curves

20 practice questions 0 video lessons Theory + worked examples

Area Between Curves

California Calculus • Standard 16.0 • Applications of Integration

Area Between Curves is a topic in Applications of Integration in the California Calculus Standards. It is aligned to Standard 16.0, which requires students to use definite integrals in problems involving area, including the area enclosed between two curves.

The area between two curves is \(\int_a^b(\text{top}-\text{bottom})\,dx\), integrated between the points where the curves intersect.

California Calculus › Applications of Integration › Area Between Curves  —  Standard 16.0

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Theory

The area between two curves is the integral of the top curve minus the bottom curve, \(\displaystyle\int_a^b (f-g)\,dx\). The limits \(a\) and \(b\) come from the intersection points of the two curves.

When two curves enclose a region, its area is built from thin vertical strips. Each strip has height top curve minus bottom curve and width \(dx\):

\[\text{Area}=\int_a^b \big(f(x)-g(x)\big)\,dx,\]

where \(f\) is on top and \(g\) on the bottom throughout \([a,b]\).

The limits \(a\) and \(b\) are the intersection points, found by setting \(f(x)=g(x)\).

Key idea: decide which curve is on top by testing a point inside the interval. Top minus bottom keeps every strip height positive.
The region enclosed between an upper curve and a lower curve The area between two curves is the integral of the top curve minus the bottom curve across the region they enclose. x y top bottom area
The region between an upper curve and a lower curve.
A vertical strip whose height is the top curve minus the bottom curve Each thin vertical strip has height top minus bottom; adding the strips gives the enclosed area. x y top − bottom
Each strip has height top \(-\) bottom.

The area between curves, and the limits:

\[\text{Area}=\int_a^b \big(\text{top}-\text{bottom}\big)\,dx\]
area is the integral of top minus bottom
\[\text{limits: solve } f(x)=g(x)\]
Check which is on top. Reversing top and bottom gives the negative of the area.

How to find the area between two curves

  1. Find the intersections by solving \(f(x)=g(x)\) for the limits.
  2. Decide which curve is on top by testing a point between them.
  3. Integrate \(\int_a^b(\text{top}-\text{bottom})\,dx\).
Example 1 — Line above a parabola
Find the area between \(y=x\) and \(y=x^2\).
Solution

They meet at \(x=0,1\); on \((0,1)\), \(x>x^2\), so integrate top \(-\) bottom.

\(\int_0^1 (x-x^2)\,dx\)\(=\)\(\left[\dfrac{x^2}{2}-\dfrac{x^3}{3}\right]_0^1\)
\(=\)\(\dfrac{1}{2}-\dfrac{1}{3}\)
\(=\)\(\dfrac{1}{6}\)
area equals one sixth
Example 2 — A line and a parabola
Find the area between \(y=x+2\) and \(y=x^2\).
Solution

They meet where \(x^2-x-2=0\), i.e. \(x=-1,2\); the line is on top.

\(\int_{-1}^{2}(x+2-x^2)\,dx\)\(=\)\(\left[\dfrac{x^2}{2}+2x-\dfrac{x^3}{3}\right]_{-1}^{2}\)
\(=\)\(\dfrac{10}{3}-\left(-\dfrac{7}{6}\right)\)
\(=\)\(\dfrac{9}{2}\)
area equals nine halves
Example 3 — Curve and a horizontal line
Find the area between \(y=4\) and \(y=x^2\).
Solution

They meet at \(x=\pm 2\); \(4\) is on top.

\(\int_{-2}^{2}(4-x^2)\,dx\)\(=\)\(\left[4x-\dfrac{x^3}{3}\right]_{-2}^{2}\)
\(=\)\(\dfrac{16}{3}-\left(-\dfrac{16}{3}\right)\)
\(=\)\(\dfrac{32}{3}\)
area equals thirty-two thirds
Example 4 — Set up the integral
How do you write the area between \(y=f\) (top) and \(y=g\) (bottom) on \([a,b]\)?
Solution

Integrate the vertical gap, top minus bottom.

\(\text{Area}\)\(=\)\(\int_a^b (f-g)\,dx\)
area is the integral of top minus bottom

Common pitfalls

Top minus bottom, in that order. Reversing them flips the sign; test a point to be sure which is on top.
Find the limits first. The bounds are the intersection points, not given numbers.
Split if the curves cross. If top and bottom switch inside the interval, break the integral at the crossing.

Frequently asked questions

How do you find the area between two curves?

Integrate the top curve minus the bottom curve between their intersection points: \(\int_a^b (f-g)\,dx\).

How do you find the limits of integration?

Set the two curves equal, \(f(x)=g(x)\), and solve. The solutions are the \(x\)-values where the region begins and ends.

How do you know which curve is on top?

Test a point between the intersections. Whichever function is larger there is the top curve on that interval.

What if the curves cross inside the interval?

Split the integral at the crossing point and use the correct top-minus-bottom order on each piece.