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Algebra 2 Statistics and probability

Probability rules (addition, multiplication)

20 practice questions 0 video lessons Theory + worked examples

Probability Rules

California Algebra 2 • Standard S-CP.7 • Statistics & Probability

Probability Rules is a topic in Statistics & Probability in the California Common Core State Standards. It is aligned to Standard S-CP.7, which requires students to apply the Addition Rule and the general Multiplication Rule and interpret the answers in context.

The addition rule gives \(P(A\cup B)\) by subtracting the overlap; the multiplication rule gives \(P(A\cap B)\) as a product.

California Algebra 2 › Statistics & Probability › Probability Rules  —  Standard S-CP.7

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Theory

Two rules combine probabilities:

  • Addition: \(P(A\cup B)=P(A)+P(B)-P(A\cap B)\).
  • Multiplication: \(P(A\cap B)=P(A)\,P(B\mid A)\).
  • For independent events, \(P(A\cap B)=P(A)\,P(B)\).
“Or” adds; “and” multiplies — and subtract any overlap.
Addition rule overlap The addition rule subtracts the overlap counted in both events. A B overlap = A and B
The addition rule subtracts the overlap \(A\cap B\).
Probability rules Probability rules Probability rules addition: P(A or B) = P(A)+P(B)-P(A and B) multiplication: P(A and B) = P(A)·P(B|A) independent: P(A and B) = P(A)·P(B)
The probability rules.

Addition and multiplication:

\[P(A\cup B)=P(A)+P(B)-P(A\cap B),\quad P(A\cap B)=P(A)\,P(B\mid A)\]
the addition rule subtracts the overlap; the multiplication rule uses a conditional probability
Mutually exclusive: the overlap is \(0\). Independent: \(P(B\mid A)=P(B)\).

How to combine probabilities

  1. For “or”, add and subtract the overlap.
  2. For “and”, multiply.
  3. Use \(P(B\mid A)\) if the events are dependent.
  4. Check for mutually exclusive or independent to simplify.
Example 1 — Addition rule
Draw one card. Find \(P(\text{king or heart})\).
Solution

Subtract the overlap (king of hearts).

\(\dfrac{4}{52}+\dfrac{13}{52}-\dfrac{1}{52}\)
\(=\)\(\dfrac{16}{52}=\dfrac{4}{13}\)
the probability is four thirteenths
Example 2 — Multiplication (independent)
Flip two coins. Find \(P(\text{two heads})\).
Solution

Independent events multiply.

\(\dfrac12\cdot\dfrac12\)\(=\)\(\dfrac14\)
one quarter
Example 3 — Mutually exclusive
Roll a die. Find \(P(2\text{ or }5)\).
Solution

These can't both happen, so no overlap.

\(\dfrac16+\dfrac16\)\(=\)\(\dfrac13\)
one third
Example 4 — Dependent multiplication
Draw two cards without replacement. Find \(P(\text{two kings})\).
Solution

The second draw is conditional.

\(\dfrac{4}{52}\cdot\dfrac{3}{51}\)\(=\)\(\dfrac{1}{221}\)
one over 221

Common pitfalls

Subtract the overlap in the addition rule unless mutually exclusive.
Use \(P(B\mid A)\) when the second event depends on the first.
Independent \(\neq\) mutually exclusive.

Frequently asked questions

What is the addition rule?

\(P(A\cup B)=P(A)+P(B)-P(A\cap B)\).

What is the multiplication rule?

\(P(A\cap B)=P(A)P(B\mid A)\).

What does mutually exclusive mean?

The events can't both happen, so the overlap is \(0\).

When do you just multiply P(A) and P(B)?

When the events are independent.