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Algebra 2 Relations and functions (advanced)

Inverse functions

20 practice questions 0 video lessons Theory + worked examples

Inverse Functions

California Algebra 2 • Standard F-BF.4 • Relations & Functions

Inverse Functions is the opening topic of Relations & Functions in the California Common Core State Standards. It is aligned to Standard F-BF.4, which requires students to build inverse functions, verifying them by composition and reading them as reflections across the line y = x.

An inverse function \(f^{-1}\) undoes \(f\), so its graph is the reflection of \(f\) across the line \(y=x\); only one-to-one functions have one.

California Algebra 2 › Relations & Functions › Inverse Functions  —  Standard F-BF.4

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Theory

The inverse function \(f^{-1}\) reverses \(f\): if \(f(a)=b\), then \(f^{-1}(b)=a\). Consequently:

  • \(f\big(f^{-1}(x)\big)=x\) and \(f^{-1}\big(f(x)\big)=x\).
  • The graph of \(f^{-1}\) is the reflection of \(f\) across \(y=x\).
  • Only a one-to-one function (passes the horizontal line test) has an inverse.
\(f^{-1}\) means the inverse function, not the reciprocal \(\dfrac{1}{f}\).
A function and its inverse The graph of the inverse is the reflection of the function across the line y = x. x y y = x f f⁻¹
\(f\) and \(f^{-1}\) are mirror images across \(y=x\).
Square and square root are inverses With the domain restricted to x at least 0, the square root undoes the square. x y √x
\(x^2\) (for \(x\ge 0\)) and \(\sqrt{x}\) are inverses.

To find an inverse:

\[y=f(x)\ \xrightarrow{\text{swap}}\ x=f(y)\ \xrightarrow{\text{solve}}\ y=f^{-1}(x)\]
replace f of x with y, swap x and y, then solve for y
Check: \(f\big(f^{-1}(x)\big)\) should simplify to \(x\).

How to find an inverse

  1. Replace \(f(x)\) with \(y\).
  2. Swap \(x\) and \(y\).
  3. Solve the new equation for \(y\).
  4. Write the result as \(f^{-1}(x)\) and, if needed, restrict the domain.
Example 1 — Find an inverse
Find the inverse of \(f(x)=2x-3\).
Solution

Write \(y=f(x)\), swap \(x\) and \(y\), then solve for \(y\).

\(y\)\(=\)\(2x-3\)
\(x\)\(=\)\(2y-3\)
\(x+3\)\(=\)\(2y\)
\(f^{-1}(x)\)\(=\)\(\dfrac{x+3}{2}\)
the inverse is x plus 3 over 2
Example 2 — Verify by composition
Verify that \(f(x)=2x-3\) and \(g(x)=\dfrac{x+3}{2}\) are inverses.
Solution

Inverses satisfy \(f(g(x))=x\).

\(f(g(x))\)\(=\)\(2\!\left(\dfrac{x+3}{2}\right)-3\)
\(=\)\((x+3)-3=x\)
the composition returns x, so they are inverses
Example 3 — Inverse of a cubic
Find the inverse of \(f(x)=x^3+1\).
Solution

Swap and solve for \(y\).

\(x\)\(=\)\(y^3+1\)
\(x-1\)\(=\)\(y^3\)
\(f^{-1}(x)\)\(=\)\(\sqrt[3]{x-1}\)
the inverse is the cube root of x minus 1
Example 4 — Restrict the domain
Why must \(f(x)=x^2\) have its domain restricted to find an inverse?
Solution

\(x^2\) fails the horizontal line test (each output has two inputs). Restricting to \(x\ge 0\) makes it one-to-one, giving the inverse \(\sqrt{x}\).

x squared is not one-to-one, so restrict the domain to x at least 0

Common pitfalls

\(f^{-1}\) is not \(\dfrac1f\). The \(-1\) marks the inverse function, not a reciprocal.
Swap first, then solve. Solving before swapping gives the original function back.
Restrict the domain for functions that aren't one-to-one, like \(x^2\).

Frequently asked questions

How do you find the inverse of a function?

Swap \(x\) and \(y\) in \(y=f(x)\) and solve for \(y\).

What does the graph of an inverse look like?

It is the reflection of the original graph across the line \(y=x\).

Which functions have an inverse?

Only one-to-one functions — those passing the horizontal line test.

Is \(f^{-1}\) the same as \(\dfrac1f\)?

No. \(f^{-1}\) is the inverse function; \(\dfrac1f\) is the reciprocal.