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Algebra 2 Polynomial functions

Remainder and factor theorem

20 practice questions 0 video lessons Theory + worked examples

Remainder and Factor Theorem

California Algebra 2 • Standard A-APR.2 • Polynomial Functions

Remainder and Factor Theorem is a topic in Polynomial Functions in the California Common Core State Standards. It is aligned to Standard A-APR.2, which requires students to know and apply the Remainder Theorem: for a polynomial p(x), p(a) is the remainder on division by x - a, so p(a) = 0 means x - a is a factor.

The Remainder Theorem says \(P(c)\) is the remainder of \(P(x)\div(x-c)\), and the Factor Theorem says \((x-c)\) is a factor exactly when \(P(c)=0\).

California Algebra 2 › Polynomial Functions › Remainder and Factor Theorem  —  Standard A-APR.2

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Theory

Two linked theorems connect values and factors of \(P(x)\):

  • Remainder Theorem: the remainder of \(P(x)\div(x-c)\) is \(P(c)\).
  • Factor Theorem: \((x-c)\) is a factor \(\iff P(c)=0\).
A zero and a factor are the same fact: \(P(c)=0\) means \(x=c\) is a zero and \((x-c)\) is a factor.
Factors are zeros A zero of the polynomial marks a factor: f(2)=0 means (x-2) is a factor. x y x=2 x=-1
Each zero \(x=c\) corresponds to a factor \((x-c)\).
Remainder & factor theorem Remainder & factor theorem Remainder & factor theorem Remainder: P(c) = remainder of P(x) ÷ (x-c) Factor: P(c) = 0 ⟺ (x-c) is a factor
The two theorems.

The theorems:

\[P(x)=(x-c)Q(x)+P(c),\qquad (x-c)\mid P(x)\iff P(c)=0\]
the remainder equals P of c; x minus c is a factor when P of c is zero
Evaluate, don't divide, to find a remainder quickly.

How to use the theorems

  1. To find a remainder by \(x-c\), compute \(P(c)\).
  2. To test a factor \(x-c\), check whether \(P(c)=0\).
  3. If \(P(c)=0\), divide out \((x-c)\) to keep factoring.
  4. Solve for unknown coefficients using a known zero.
Example 1 β€” Remainder theorem
Find the remainder when \(P(x)=x^3-4x+1\) is divided by \(x-2\).
Solution

Evaluate \(P(2)\).

\(P(2)\)\(=\)\(8-8+1\)
\(=\)\(1\)
the remainder is 1
Example 2 β€” Factor theorem
Is \(x-3\) a factor of \(P(x)=x^3-2x^2-2x-3\)?
Solution

Check whether \(P(3)=0\).

\(P(3)\)\(=\)\(27-18-6-3\)
\(=\)\(0\)

Since \(P(3)=0\), \(x-3\) is a factor.

yes, because P of 3 equals 0
Example 3 β€” Find a value
\(P(x)=x^3+kx-6\) has \(x-1\) as a factor. Find \(k\).
Solution

Set \(P(1)=0\).

\(1+k-6\)\(=\)\(0\)
\(k\)\(=\)\(5\)
k equals 5
Example 4 β€” Use a known zero
Given \(P(2)=0\) for \(P(x)=x^3-3x^2+4\), factor out one factor.
Solution

\(P(2)=0\) means \((x-2)\) divides \(P\).

\(x^3-3x^2+4\)\(=\)\((x-2)(x^2-x-2)\)
\(=\)\((x-2)(x-2)(x+1)\)
factors as x minus 2 squared times x plus 1

Common pitfalls

Use \(c\), not \(-c\): for \(x-2\), evaluate \(P(2)\).
\(P(c)=0\) means factor; a nonzero value is just the remainder.
A zero gives one factor β€” keep dividing for the rest.

Frequently asked questions

What is the Remainder Theorem?

The remainder of \(P(x)\div(x-c)\) equals \(P(c)\).

What is the Factor Theorem?

\((x-c)\) is a factor of \(P(x)\) exactly when \(P(c)=0\).

How do you test if \(x-c\) is a factor?

Evaluate \(P(c)\); if it is \(0\), then \(x-c\) is a factor.

How are zeros and factors related?

Each zero \(x=c\) gives a factor \((x-c)\), and vice versa.